Question

in a two variable sample the sum of the squares of the differences in ranks in 33 and the rank correlation coefficient is 0.8 . find the number of pairs of observation .​

Answer 1

Answer:

Answer is below

Explanation:

If the rank correlation coefficient is 0.6 and the sum of squares of difference of ranks is 66, then find the number pairs of observations.

Answer 2

Given that di² is 33 and the rank correlation coefficient is 0.8 . find the number of pairs of observation

Explanation:

• P=1−6 *∑di² /n(n²  −1)
• 0.8= 1-6*(6×33)/n(n²  −1)
• (6×33)/n(n²  −1) = 0.2
• n(n²  −1) = (6×33)/0.2 =990
• n = 10
• 10(10²   −1)=10(99)=990

• The number of pairs of observation n=10, n(n²  −1) =990

 

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