Question

In a vessal 2g O2, 2g H2 and 2g N2 are present. Which has largest number of atoms

Answer 1

Answer:

2gm of H2

Explanation:

as we know very well that

32gm of O2 = 1 mole

2gm of O2 = 0.0625 mole

again we know in case of N2 there is a same case alike O2 but in case of H2 , 2gm of H2=1 mole .

Answer 2

2g H₂ has the largest number of atoms.

Given: mass of O₂, m₁ = 2g

           mass of H₂, m₂ = 2g

           mass of N₂, m₃ = 2g

To Find: Number of atoms in O₂, N₁

              Number of atoms in H₂, N₂

              Number of atoms in N₂, N₃

Solution:

To calculate the number of atoms, the formula used:

• Number of atoms, N = number of moles x Avogadro's number (Nₐ)
• Nₐ = 6.02 x 10²³atoms/ions/molecules
• number of moles, n = mass (m) / molar mass(M)

For O₂:

Number of moles, n₁ = m₁ / Molar mass of O₂

Molar mass of O₂ = 32g

n₁ = 2/32

    = 1/16 mol

N₁ = n₁ x Nₐ

    = 1/16 x 6.02 x 10²³

    = 0.376 x 10²³atoms

N₁ = 0.376 x 10²³atoms

For H₂:

Number of moles, n₂ = m₂ / Molar mass of H₂

Molar mass of H₂ = 2g

n₂ = 2/2

    = 1 mol

N₂ = n₂ x Na

    = 1 x 6.02 x 10²³

N₂ = 6.02 x 10²³atoms

For N₂:

Number of moles, n₃ = m₃ / Molar mass of N2

Molar mass of N₂ = 28g

n₃ = 2/28

    = 1/14 mol

N₃ = n₃ x Nₐ

    = 1/14 x 6.02 x 10²³

    = 0.43 x 10²³

N₃ = 0.43 x 10²³atoms

Hence, 2g H₂ has the largest number of atoms i.e. 6.02 x 10²³atoms.