Question

In a violent storm, a tree got bent by the wind. The top of the tree meeta the ground at an angle of 30°, at a distance of 30m from the root. At what height from the bottom did the tree got bent? What was the original height of the tree?

Answer 1

Heya Frnd........☺

Let the height from the bottom to the bent portion be $h$

NOW,

$\tan(30) = \frac{h}{30}$

$= > \: \frac{1}{ \sqrt{3} } = \frac{h}{30}$

So,

$h \: = \: \frac{30}{ \sqrt{3} } m \: ...........ans \:( 1 )$

Now

$total \: height \: = \: h \: + \: 30$

$= \: \frac{30}{ \sqrt{3} } + 30$

$= > \: \frac{30 \: + \: 30 \sqrt{3} }{ \sqrt{3} }$

$= > \: 69.49m........( \sqrt{3} = 1.732)$

$............ \: \: ANS$

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$HOPE \: IT \: WILL \: HELP \: U .........$