In a Wheatstone's bridge, the four resistance arms of the bridge are AB=4ohm, BC=6ohm,
CD=8ohm &DA=2ohm. A cell of emf 2V & negligible internal resistance is connected arms AC
& a galvanometer of resistance 10ohm is connected between B & D. Find the current
through the galvanometer.
Answers
Answered by
1
Answer:
ahshsbsvjwyejapwuejrbbvchsurkwowokld. djduriekeheiwtgsjsirijhfdhdu.
Explanation:
yhahahsjsodjdjdjsjjsosisnsbahdude
Similar questions