Question

In a Wheatstone's bridge, the four resistance arms of the bridge are AB=4ohm, BC=6ohm,
CD=8ohm &DA=2ohm. A cell of emf 2V & negligible internal resistance is connected arms AC
& a galvanometer of resistance 10ohm is connected between B & D. Find the current
through the galvanometer.​

Answer 1

Answer:

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Explanation:

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