in a year n the 259th day of the year is a saturday. in the year n+l the 222th day of the year is also a saturday. what is the 119th day of the year n-l?
Answers
Step-by-step explanation:
as 259th day of year N and 222th day of year N+1 is same i.e saturday, so number of day between above 2 day is must be divided by 7..
no. of days btwn dis 2 day may b (366-259)+222=329----(1) or (365-259)+222=328------(2)
as 329 is divided by 7 so year N is leap year son Year N-1 is not a leap year....
now number of day btwn 119th of N-1 and 259th of N is (365-119)+259 =505
now 505/7 gives remainder 1 , so 504 is divided by 7, so 120th day of N-1 is saturday...so 119th day of N-1 is Friday
Answer:
119th day of the year N-1 is a Friday.
Step-by-step explanation:
Consider the Nth year.
In the Nth year, 259th is a Saturday.
In the N+1 year, the 222nd day is also Saturday.
So there should be 0 odd days between these days.
But We don’t know if the Nth year is a leap year or not.
Case 1:
Let us assume Nth is an ordinary year
Then the number of days between these 2 days =>
(365 - 259) +222 = 328 days
In 328 days, we have 1 odd day. So we can say that Nth year is not an ordinary year.
Case 2:
Let us take the Nth year as a leap,
Number of days between these 2 days => (366 - 259 ) + 222= 329 days
In 329 days, we have 0 odd days. So we can say that Nth year is a leap year
As the Nth year is a leap, the (N-1)th year is not a leap year.
Number of days between 259 th day of Nth year and 119th day of (N-1)th year
= 259 + (365-119)
= 505 days
The number of odd days in 505 days =>1 odd day
Therefore , 119th day of the year N-1 => Saturday -1 = Friday.
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