in a young double slit experiment the intensity is high at a point where the path difference is Lambda by 6 where Lambda is wavelength of the light used if I know dinners maximum intensity I /Io then what will be its equal to?~
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phase difference = 2π∆x / lemda
= 2π/ lemda ×lemda/6
= π/3
using I = Io cos^2 phai/ 2
we have,
I = 3/4 Io
I/Io = 3/4
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