Question

In a Young’s double slit experiment, the distance between the slits is given to be 1mm and the distance between screen and slits to be 1m. The second order fringe is at a distance of 1mm from the center. Calculate the wavelength of light used (in Ao​

Answer 1

Answer:

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Answer 2

Answer:

In Young’s double-slit experiment, the distance between the slits is given to be 1mm and the distance between screen and slits to be 1m. The second-order fringe is at a distance of 1mm from the center. The wavelength of light used is $500A$⁰

Explanation:

The young's double-slit experiment gave a definite proof for wave characteristics of light

In the experiment, two parallel slits separated by a distance $d$ acts as the light source as the wave hit a screen at a distance $L$ from the slits  we get an interference pattern over the screen

The condition for constructive interference is

$dsin$θ$=m$λ

and the condition for destructive interference is

$dsin$θ$=(m+1/2)$λ

where $m=0,$±$1,$±$2$ etc

from the question, we have

the distance between the slits $d=1mm=0.001m$

the distance between the screen and slit $L=1m$

order $m=2$

the fringe distance $y=1mm=0.001m$

we can use the first equation to get the wavelength of the light

from the figure, we can write $sin$θ$=y/L$

substitute the given values

λ$=dy/Lm=0.001*0.001/1*2=0.5*10^{-6}=500*10^{-10}m$

the wavelength of the light used is λ$=500A$⁰