Physics, asked by yasharsh1878, 11 months ago

In a Young’s double slit experiment the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to central fringe on the screen will be
(A) (√3 + 1)⁴ :16 (B) 25 : 9
(C) 9 : 1 (D) 4:1

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Answered by Abhis506

0

The answer is (D) 4:1.......

Answered by indian2020

0

Answer:

bro ans.....c)9:1 ..100%%%% correct........

pakkawala

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