In a Young’s double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range –30° ≤ θ ≤ 30° is:
(A) 640 (B) 320
(C) 321 (D) 641
Answers
Answered by
34
Question :
In a Young’s double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range –30° ≤ θ ≤ 30° is:
Given :
λ = 500 nm
d = 0.320 mm
θ = 30°
solution ;
we know that in YDSE.
path difference ;
dsinθ= nλ
put the given values after that ;
no of maxima from -30° to 30° is
= 2n+1
= 2× 320+1
= 641
Answered by
4
Given :
λ = 500 nm
d = 0.320 mm
θ = 30
path difference
d sinθ = nλ
n =d sinθ/λ
after putting the values you get
n = 320
maximum no bright fringes
= 2n+1
= 2× 320+1
= 641
Similar questions