In a zoo there are days and ducks if the head or counter there are 180 while dial 100 448 what will the number of the deals in the zoo
Answers
Answered by
5
The answer is given below :
Let us consider that there are x number of deer and (180 - x) number of ducks in the zoo.
Then,
4x + 2(180 - x) = 448
=> 4x + 360 - 2x = 448
=> 2x = 88
=> x = 44
So, number of deer is 44
and
number of duckes is (180 - 44) = 136.
Thank you for your question.
Let us consider that there are x number of deer and (180 - x) number of ducks in the zoo.
Then,
4x + 2(180 - x) = 448
=> 4x + 360 - 2x = 448
=> 2x = 88
=> x = 44
So, number of deer is 44
and
number of duckes is (180 - 44) = 136.
Thank you for your question.
Answered by
6
hay!!
Dear friend -
Let there consider number = x
and then number of ducks= (180-x)
So,
=> 4x+2(180-x) =448
=> 4x+360-2x=448
=> 4x-2x=448-360
=> 2x=88
=> x=88/2
=> x=44
so, number of deer=>44
and number of ducks => (180-44) =136
I hope it's help you
Dear friend -
Let there consider number = x
and then number of ducks= (180-x)
So,
=> 4x+2(180-x) =448
=> 4x+360-2x=448
=> 4x-2x=448-360
=> 2x=88
=> x=88/2
=> x=44
so, number of deer=>44
and number of ducks => (180-44) =136
I hope it's help you
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