Question

in a²/b²+b²/c²+c²/a²+a/c+b/a+c/a in this equation there is a point of cancellations of terms. if how and which terms will be crossed.​

Answer 1

Answer

a², b², c² are in A.P

→ b² - a² = c² - b² (b-a)(b + a) = (c −b)(c + b)

(b-a) (c + b) (c-b) (b + a) =

(b-a) (c + b)(c + a) (c-b) (b + a)(c + a)

(b+c-c-a) (c + b)(c + a) (c+a-a-b) (b + a)(c + a) =

1 1 1 1 - =

c+a

b+c

a+b

1 1 1 b+c'c+a'a+b are in A.P

a+b+c a+b+c a+b+c b+c c+a a+b A.P are in

a b +1, b+c c+a A.P C +1,a+b+1 are in

a b C b+c'c+a'a+b are in A.P

Answer 2

Answer:

We have,

a2,b2,c2 are in A.P

⇒b2−a2=c2−b2

⇒(b−a)(b+a)=(c−b)(c+b)

⇒(c+b)(b−a)=(b+a)(c−b)

⇒(c+b)(c+a)(b−a)=(b+a)(c+a)(c−b)

⇒(c+b)(c+a)(b+c−c−a)=(b+a)(c+a)(c+a−a−b)

⇒c+a1−b+c1=a+b1−c+a1

b