Question

In AABC bisectors of exterior angles Band
C meet at O. Given ZBAC = 60° and
ZABC = 70°, find ZBOC​

Answer 1

Answer:

In △ABC,

∠ABC+∠ACB+∠BAC=180

∠ABC+70+50=180

∠ABC=60∘

∠OCB=21(180−∠ACB)

∠OCB=21(180−50)

∠OCB=65∘

∠OBC=21(180−∠ABC)

∠OBC=21(180−60)

∠OBC=60∘

In △OBC,

∠OCB+∠OBC+∠BOC=180

65+60+∠BOC=180

∠BOC=180−125

∴∠BOC=55∘