Question

In AABC, if 2 ,A = 3 B = 6 C, calculate the measures of all the angles

Answer 1

Answer:

Step-by-step explanation:

let 2A=3B=6C=k

A=k/2

B=k/3

C=k/6

sum of angles in a triangle=180

k/2+k/3+k/6=180

2k+3K+k=180*6

k=180

now

A=k/2=180/2=90

B=k/3=180/3=60

C=k/6=180/6=30

Answer 2

Answer:

A = 90; B = 60; C = 30

Step-by-step explanation:

2A = 3B = 6C ...(1)

A + B + C = 180 (Angle Sum Property Of a triangle) ... (2)

then,

2A = 3B so, A = 3B/2 (from (1)) .... (3)

and, 3B = 6C so, B = 2C i.e, C = B/2 (form (1)) ... (4)

in (2) =>

3B/2 + B + B/2 = 180 (from (3) and (4))

Taking B common,

B( 3/2 + 1 +1/2) = 180

B(4/2 + 1) =180

B (2+1) = 180

B(3) = 180

B = 60

Then, Putting B = 60 into (3) ->

A = 3(60)/2

A = 90

Then, Putting B = 60 into (4) ->

C = B/2

C = 60/2

C = 30