Question

In AABC, point D is on kepentic so that ZBAC - ADC
then prove that CA² =CBxCD​

Answer 1

Answer:

In ∆BAC and ∆ADC, ∠BAC ≅ ∠ADC [Given] ∠BCA ≅ ∠ACD [Common angle] ∴ ∆BAC ~ ∆ADC [AA test of similarity] ∴ CA/CD = CB/CA [Corresponding sides of similar triangles] ∴ CA × CA = CB × CD ∴ CA2 = CB × CD.

Step-by-step explanation:

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