In ∆ABC A=2x-5° , B=5x+5°, C=3x+50° .find the value of k
Answers
Answered by
0
Answer:
x = 13°
Step-by-step explanation:
sum of all angles in a triangle = 180°
A + B + C = 180°
2x - 5 + 5x + 5 + 3x + 50 = 180°
10x + 50° = 180°
10x = 130°
x = 130°/10
x = 13°
Hence, the value of x = 13°
Similar questions