Question

In ΔABC, ∠A = 50° and the external bisectors of ∠B and ∠C meet at O as shown in figure. The measure of ∠BOC is

Answer 1

Answer:

115

Step-by-step

In triangle ABC

∠A + ∠B + ∠C = 180°

and

∠A = 50° (given)

Then,

∠2∠OBC + 2∠BCO = ∠A+180°

⇒ ∠OBC + ∠BCO = 1/2

=> ∠+90° = 50/2 + 90 = 115°

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Answer 2

Answer:

65 is the answere