In ABC, a = 8, b = 11, and m ∠C = 125. What is the area of ABC? *
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Given :- In ABC, a = 8, b = 11, and m ∠C = 125°. What is the area of ABC ?
Solution :-
from image we can see that,
- BC = a = 8
- AC = b = 11
- ∠C = 125° .
we know that,
- Area of ∆ = (1/2) * BC * AC * sin C { angle between sides we take. }
putting values we get,
→ Area of ∆ = (1/2) * 8 * 11 * sin 125°
→ Area of ∆ = 4 * 11 * sin 125°
→ Area of ∆ = 44 * sin 125°
→ Area of ∆ = 44 * 0.82
→ Area of ∆ ≈ 36.08 unit². (Ans.)
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