In ABC, a = 8, b = 11, and m ∠C = 125. What is the area of ABC? *
Answers
Answered by
0
Answer:
hope you understand mate
Attachments:
Answered by
0
Given :- In ABC, a = 8, b = 11, and m ∠C = 125°. What is the area of ABC ?
Solution :-
from image we can see that,
- BC = a = 8
- AC = b = 11
- ∠C = 125° .
we know that,
- Area of ∆ = (1/2) * BC * AC * sin C { angle between sides we take. }
putting values we get,
→ Area of ∆ = (1/2) * 8 * 11 * sin 125°
→ Area of ∆ = 4 * 11 * sin 125°
→ Area of ∆ = 44 * sin 125°
→ Area of ∆ = 44 * 0.82
→ Area of ∆ ≈ 36.08 unit². (Ans.)
Learn more :-
in triangle ABC seg DE parallel side BC. If 2 area of triangle ADE = area of quadrilateral DBCE find AB : AD show that B...
https://brainly.in/question/15942930
2) In ∆ABC seg MN || side AC, seg MN divides ∆ABC into two parts of equal area. Determine the value of AM / AB
https://brainly.in/question/37634605
Attachments:
Similar questions