In ABC,AB=26 cm , BC=28 cm and the altitude AD=24cm.CalcuteAC
Answers
Answer:
it is given that in a triangle ABC,
AB=26 cm,
BC=28 cm,
altitude(height)=24 cm
then AC value can be calculated by,
let AD the altitude be a median which divides BC into half so,
BC=DC + BD
DC = 14 cm
now we get two right triangles ABD and ADC
IN A RIGHT TRIANGLE ADC we have,
AC^2 =AD^2 + DC^2
AC^2 = 24^2 + 14^2
AC^2= 576+196
= 772
AC = square root of 772
= 27.8 cm
Step-by-step explanation:
it is given that in a triangle ABC,
AB=26 cm,
BC=28 cm,
altitude(height)=24 cm
then AC value can be calculated by,
let AD the altitude be a median which divides BC into half so,
BC=DC + BD
DC = 14 cm
now we get two right triangles ABD and ADC
IN A RIGHT TRIANGLE ADC we have,
AC^2 =AD^2 + DC^2
AC^2 = 24^2 + 14^2
AC^2= 576+196
= 772
AC = square root of 772
= 27.8 cm