In ABC , AB = AC = 9 and BC =14 . Find tanB .
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Answered by
2
Given:
In Δ ABC , AB = AC = 9 and BC =14 .
To find:
tan B
Solution:
Since the given triangle is an isosceles triangle, we can draw a line perpendicular to one side, that divides the side into 2 equal halves.
Construction: Draw a perpendicular line from point A on line BC and mark it as D.
BD = DC = BC/2 = 14/2 = 7 cm.
AD² = AB² + BD² = 9² + 7² = 81 + 49 = 130
∴ AD = √130 = 11.4
tan B = AD / BD (as tan ∅ = opposite side / adjacent side)
⇒ tan B = 11.4 / 7
∴ tan B = 1.628
Answered by
4
Answer:
.
Construction: Draw a perpendicular line from point A on line BC and mark it as D.
ACCORDING TO THE QUESTION
we have
BD = DC = BC/2 = 14/2 = 7 cm.
Pythagoras theory
AD² = AB² + BD²
PUTTING the value in formula
= 9² + 7² = 81 + 49 = 130
∴ AD = √130 = 11.4
tan B = AD / BD
we know that
(as tan ∅ = opposite side / adjacent side)
⇒ tan B = 11.4 / 7
∴ tan B = 1.628
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