Question

in ABC,AB=AC and D is a point in side BC such that AD bisect angle BAC show that AD is perpendicular bisector of side BC

Answer 1

considering the triangles ABD and ACD
AB=AC,AD is angular bisector of BAC so angles BAD=CAD,AD is common side
so by SAS property both triangles are congruent
hence all corresponding sides and angles are equal
so BD=CD, D is the mid point of BC
angle BDA=CDA, but also that angle BDC is 180
as BDC=BDA +CDA,BDA=CDA=90
hence AD is a perpendicular bisector of side BC

Answer 2

Answer:

here is your answer

Step-by-step explanation:

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