In ∆ABC, AB = AC and <B = 50° . Then <A = ?
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Answer:
80°
Step-by-step explanation:
we know that,
ΔABC is an isosceles triangle. (Since,AB=AC)
we also know that,
<B=<C
by angel sum property:
<A+<B+<C=180°
<A+<B+<C=180°<A+2<B=180°
<A+2<B=180°
<A+2(50°)=180°
<A+100°=180°
<A=180°-100°
<A=80°
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