Question

In ∆ABC , AB = AC , D is the midpoint of BC. Show by SSS criterion that ∆ABC = ∆ACD​ who ever will give this answer with step by step explanation will be marked as brilliant ​

Answer 1

Step-by-step explanation:

plz mark as brainliest...

Answer 2

answer:-

a) In triangle,ABD and ACD

AD=AD

AB=AC

BC=CD[ D is midpoint at BC]

b) by using part a of the,we get ∆ABD≈ ∆ACD.......sss criterion