In ∆ABC , AB=AC.If BAC +ACB =130°, ACB is - a) 130°, b) 50°, c) 80°,d) 100°
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I am sure as it is 130 as it the quadrilateral which is inscribed in a circle is cyclic quadrilateral so in cyclic quadrilateral sum of two consecutive angle is 180...
therefore
angle abc = 180 ° - 130 °
= 50°
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