in ∆ ABC, AB =BC =6cm.If a circle is drawn with center at B. and radius 2cm which intersect AB and BC at E and D. then ∆ ABC congurent ∆EBD.
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Step-by-step explanation:
angle b = angle b (common)
AB = 6cm ≠ EB = 2cm
BC = 6cm ≠ BD = 2cm
hence the two triangle are not congruent
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