Question

In ∆ABC, ∠ACB = 90°. Seg CD ⊥ seg AB, seg DE ⊥ SEG CB. Show that CD² × AC = AD × AB × DE​

Answer 1

Answer:

In ABC, ACB = 90^o Seg CD side AB and seg DE side CB show that ...

1 answer

In ABC, ACB = 90^o Seg CD side AB and seg DE side CB show that CD^2 × AC = AD × AB × DE

Step-by-step explanation:

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