Question

(In ∆ABC, ACB = 90o

, ABC = θ, BC = 12 units, AB = 13 units. Find sin θ, cos θ, sin

(90 – θ), cos (90 – θ).​

Answer 1

Answer:

using Pythagoras theorem,

$ac2 + bc2 = ab2$

$(12)2 + ac2 = (13)2$

144+ac2 =169

ac2 =169-149

ac2=25

ac=√25

sin =5/13

cos==12/13