Question

In ∆ ABC, AD is the bisector of ∠A and as well as the bisector of BC. Prove that ∆ABC is an isosceles triangle.

NOTE: AD is the bisector of BC, not the perpendicular bisector of BC.
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Answer 1

Step-by-step explanation:

1) Since AD is the bisector of Angle A.

2) And, BD = DC.

3) Therefore, We can conclude that ∆ABC has to be an isosceles triangle.

Answer 2

Answer:

Hope my answer helps you mate :-)

Step-by-step explanation:

Given:- Angle BAD=DAC,BD=DC

Now in Triangle ABD And ADC

BD=DC. (given)

Angle. BAD=DAC. (given)

AD=AD. (common)

Therfore Triangle ABD≈ADC. (By SAS)

Therfore AB=AC. (By CPCT)

Therefore ABC is isosceles triangle whose two sides are equal.

Its correct mate Not incorrect

You can also write Angle B=C (By CPCT)

Mark as brainliest answer ☑️⭐✔️