Question

in ∆ABC and ∆DEF ,AB=DE,BC=EF and <B=<E

Answer 1

Sry fr late
Take triangle def
Draw dg perpendicular to ef
Now, angle dge=dgf construction r
De=df. Given. H
dg=dg common. S
So these two triangle s are congruent
Angle e=angle f by cpct

We know angle b= angle e
Angle e= anle. F
So. Angle b= f