Question

In ∆ABC, Angle A = 82° and the interior bisector of angle B and angle C intersect each other at point P. Find angle BPC.
please answer!​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

.HERE IN triangle ABC ,

ANGLE A =82 DEGREE

WE KNOW THAT SUM OF INTERIOR ANGLES OF Q TRIANGLE IS 180 DEGEREE,

SO A+B+C=180 DEGREE

=>B+C=180-82=98 DEGREE

WE GET ANGLE B+C=98 DEGREE

CASE 2:

HERE NOW INTERIOR BISECTOR OF ANGLE B AND ANGLE C INTERSECT AT EACH OTHR AT POINT P.

THEY AGAIN FORM A TRIANGLE BPC.

NOW AGAIN SUM OF INTERIOR ANGLES OF A TRIANGLE IS 180 DEGREE.

SO B+C+P=180

=>P=180 -98=82 DEGREE

SO ANGLE OF BPC IS 82 DEGREE..