Math, asked by hbaibhab, 11 months ago

In ∆ABC,angle A=90,AB=5cm,BC=13cm and AD perpendicular BC.Then the length of AD is-​

Answers

Answered by mageshkulkarni407
9

Answer:

  1. Use Pythagoras theorem. in triangle abc.( given angle A is equal to 90 ab is equal to 5 BC is equal to 13 and 8 is equal to ad is perpendicular to BC).

Step-by-step explanation:

BC2 =BA2 + AC2 = 169-25=AC2. =144. Ac=12cm

Answered by ethanprince4444
20

area of triangle = (1/2) × base×height

if we take AC as perpendicular then AB will be base.

then area of triangle = (1/2)× 5×12 = 30 cm²

also, by Pythagoras' theorem, 

BC² = AC² +AB²

      =12² + 5² = 169

BC = 13 cm

now, if AD is perpendicular then BC is the base

area of triangle = (1/2)× BC ×AD

30 = (1/2)× 13×AD

AD = 60/13 =4.61 cm

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