Question

what is the hypotenuse measure of an right isosceles triangle whose area is 8 sq cm

Answer 1

here, we have AB = 8cm.
let BC=AC=n...

Then apply Pythagoras theorem,[ h2=p2+b2=>AB2=BC2+AC2h2=p2+b2=>AB2=BC2+AC2 ]

64       = n2+n2n2+n2
              = 2(n2)2(n2)

n2=64/2n2=64/2
n2=32n2=32
n=(√32)=5.65685424949n=(32)=5.65685424949


So, your other sides are 5.66 cm, each.
HOPE IT HELPS You
PLEASE MARK IT AS BRAINLIEST.

Answer 2

Answer:

8√2

Step-by-step explanation:

Because the triangle is isosceles Triangle so both sides are same other than hypotenuse.

Therefore,

Let one side be = x

Therefore,

By Pythagorus  Theorem

(Hyp)² = (Base)² + (Prependicular)²

(Hyp)² = 8*8 + 8*8

Hyp = √64 + 64

Hyp = √128

Hyp = 8√2

So this is the easiest way and simplest way to solve this question.

If u have any doubt ask me.

Please mark it as Brainliest.