In ∆ABC angle A is x degree angle B is 3x² angle C is y degree. If 3y-5x=30 ,prove that the triangle is a right angled triangle
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∠A = x
∠B= 3x²
∠C=y
By angle sum property
∠A +∠B+∠C=180 degree
x+3x²+y=180......(1)
3y-5x=30
y=(30+5x)/3
put y in (1)
x+ 3x²+ (30+5x)/3 = 180
3x+ 9x² + 30 + 5x = 540
9x²+8x+510=0
solve for x and get angles A, B,C
if any one angle is 90 then it will be right angle triangle
∠B= 3x²
∠C=y
By angle sum property
∠A +∠B+∠C=180 degree
x+3x²+y=180......(1)
3y-5x=30
y=(30+5x)/3
put y in (1)
x+ 3x²+ (30+5x)/3 = 180
3x+ 9x² + 30 + 5x = 540
9x²+8x+510=0
solve for x and get angles A, B,C
if any one angle is 90 then it will be right angle triangle
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