Question

in ΔAbc angle B = 90° angle A =30° AC=14 find Ab and Bc​

Answer 1

here in triangle ABC

B = 90° , A = 30°

A + B + C = 180°

30 + 90 + C = 180°

C = 180 - 120

C = 60°

by 30°-60°-90°

BC= 1/2× AC ---(side opposite to 30°)

BC = 1/2×20

BC = 10 cm

AB =√3/2×AC ----(side opposite to 60°)

AB = √3/2×20

AB = 10√3