In ∆ ABC angle B = 90° BD perpendicular to AC. If AC = 10cm and AB=6cm, find AD.
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Answer:
Given:
∠ABC=90
o
,BD⊥AC,
BD=8 and AD=4 as in diagram.
Let ∠ACB=x
⇒∠CBD=90−x
⇒∠ABD=x
⇒∠BAD=90−x
⇒ΔABC,ΔADB and ΔBDC are similar
CD /BD= AD/DB
CD/8=8/4
CD=8×8/4
=16cm
PLEASE MARK AS BRAINLIEST
=16cm.
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