Question

In ∆ABC, Angle C = 3 and Angle B = 2(Angle A + Angle B)
Find all three angles


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Answer 1

Answer ✍️

We know that in a ∆ the sum of all the interior angles is 180°

|_ A + |_ B + |_ C = 180°...... (1)

Also give that

∆C = 3∆B and 3∆B = 2∆A + 2∆B

∆A = ∆B / 2

Substituting values in (1) we get..

∆B/2 + ∆B + 3∆B = 180°

∆B =40°

∆A = 20°

∆C =120°

Hope it helps uhh ❤️

Answer 2

Answer:

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Let angle A = x

Angle B = y

As mentioned in the question angle C = 3 angle B = 3y

Angle C is also given as 2(Angle A + Angle B)

= 2(x+y)

So,

3y = 2(x+y)

y = 2x

So angle C = 3y = 6x

We know that sum of all the 3 angles in a triangle = 180deg

Therefore,

Angle A+ Angle B + Angle C = 180

x+ 2x+ 6x = 180

x = 20

Hence Angle A = 20

Angle B = 40

Angle C = 120

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