Question

In ∆ABC , angle C = 3 angle B = 2(angle A + angle B)

Answer 1

Explanation:

Explanation:

$\huge \bf \red{ \boxed{ \boxed {\ulcorner{ \mid{ \overline{ \underline{ANSWER}} \mid}\urcorner}}}}$

$\bf{QUESTION - }$

In a ΔABC , ∠C = 3∠B = 2(∠ A + ∠ B ) . Find the angles .

→ let ∠a = x° and ∠b = y°

Then

∠C= 3∠B= 3(y°)

Now,

→ ∠C = 2(∠A+∠B)

=> 3y = 2(x+y)

=> 2x - y = 0............(1)

we know that the sum of angles of triangle is 180°

.°. ∠A + ∠B + ∠C = 180°

=> x + y + 3y = 180

=> x + 4y = 180...........(2)

on multiplying (1) by 4 and adding result with (2), we get

8x + x = 180

= 9x = 180

=> x = 180/9

=> x = 20

putting x = 20 in equation (1)

we get

→ y=(2×20)

→ y=40

thus,

x=20

y=40

Hence

→ ∠a = 20°

→ ∠a = 20° → ∠b=40°

$\sf{ \angle \: c = (3 \times 40) = \: 120 \degree}$

Answer 2

Refers to ATTACHMENT....!!!!