In ∆ABC ,angleA be=90,AD=DC,AB=12,BC=6.5,find area of ∆ADB...
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i think there seems to be some mistakes in your question
Nithishmahi:
It's correct
Plz answer it bava..
what bava
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if ad=dc
then ar(∆adb)=½ar(abc)
ar(∆abc) = ½×base×height
=½×12×6.5
=6×6.5
=39 unit²
ar(adb) =39/2
=18.5unit²
then ar(∆adb)=½ar(abc)
ar(∆abc) = ½×base×height
=½×12×6.5
=6×6.5
=39 unit²
ar(adb) =39/2
=18.5unit²
it is correct and hope u understood it
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