Math, asked by nujatmulani304, 4 months ago

In ∆ABC, angleB=90°.find the following results, sinA×cosC tanA/cotC 1+tan²A?​

Answers

Answered by usjadhav2001
0

Answer:

follow me

make as brainliest ans

likes my All ans

ol

Step-by-step explanation:

Sins, Triangle of ABC whose angle B=90° and

TanA=1/13

Therefore, TanA=1/V3=BC/AB. [From to angle A]

Therefore,Let, BC=k and AB=v3k

According to pithagoraous rule,

AC?=AB?+BC?

»AC2=(v3K)2+(k)

»AC?=3k?+k?

» AC2=4K2

Therefore, AC=2k

And sinA=BC/AC=k/2k=1/2

cosA=AB/AC=v3k/2K3DV3/2

sinC=AB/AC=v3k/2k=v3/2

cosC=BC/AC=k/2k=1/2

:. sinA.cosC+cosA.sinC

=1/2x1/2+v3/2xv3/2

=1/4+3/4

=1+3/4

=4/4

= 1

Previous Question
Next Question
Similar questions
Math, 1 month ago
\displaystyle\sf\lim\limits_{x\to\infty}\sqrt[x]{\dfrac{x!}{x^{x}}}Or\displaystyle\sf\lim\limits_{x\to\infty}\left(\dfrac{x!}{x}\right)^{\left(\dfrac{1}{x}\right)}​...
Math, 1 month ago
the number 3.7452 correct to 2 decimal places.
Math, 1 month ago
find 'x' if 2³ = 1/2x​...
Hindi, 4 months ago
क्रोपिंग टूल कंप्यूटर नोट ​...
Math, 4 months ago
which term of .21,18,15,....is -81?​
English, 10 months ago
Write a letter to ur cousin who ;lives abroad and tell her about the precautionary measure that have been taken against the corona viruse in ur country...
Business Studies, 10 months ago
Describe some examples of franchising by Indian firms.
Art, 10 months ago
विचार करून उत्तर द्या एक व्यापारी असतो त्याच्या जवळ 3 पोती नारळ असतात एका पोत्यात 30 नारळ याप्रमाणे 3 पोत्यात 90 नारळ असतात तो प्रवासासाठी निघालेला असतो त्या हायवेवर 30 टोलनाके असतात प्रत्येक नाक्यावर कररूपाने एका पोत्यासाठी एक नारळ नारळ दिल्यानंतर व्यापा-याकडे किती नारळ शिल्लक राहतील...