Question

In ∆ABC ∠B= 90°, AB= 9, BC= 4 then find AC=.​

Answer 1

Answer:

FOR PERIMETRE :-

FOR angle :-∠A = ∠45°,∠B = ∠45°

Step-by-step explanation:

FOR PERIMETRE :-

perimetre of triangle = sum of all sides

                                   =9+4+x

                                   = 11+x

                                   =x=8

                                  =8cm

hence, AB = 9cm; BC = 4cm; AC = 8cm

angle of triangle = sum all sides= 180°

                            =180°-90°

                            =90°

hence, ∠A= 45° ; ∠B=90° ; ∠C=45°