Question

In ∆ABC , B = 90° and AC = 8√2 . If AB = BC , then find AB

Answer 1

By Pythagoras theorem --

AB² + BC ² = AC²

= AB ² + AB ² = ( 8√2 )² ( Since AB = BC )

= 2AB ² = 128

AB ² = 64

AB = 8 Ans.

Answer 2

AB = BC....let AB = x= BC....(1)
by pythagoras theorem
AC ^2= AB^2. +BC^2
=>AC^2 = 2x^2 .....from (1)
=>(8root2)^2= 2x^2
=>64 * 2 = 2x^2
=>64 = x^2
=>8 = x....hence AB = 8unit.from (1)..

thank you