In ∆ABC , B = 90° and AC = 8√2 . If AB = BC , then find AB
surbhi1684:
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Answered by
3
By Pythagoras theorem --
AB² + BC ² = AC²
= AB ² + AB ² = ( 8√2 )² ( Since AB = BC )
= 2AB ² = 128
AB ² = 64
AB = 8 Ans.
AB² + BC ² = AC²
= AB ² + AB ² = ( 8√2 )² ( Since AB = BC )
= 2AB ² = 128
AB ² = 64
AB = 8 Ans.
how the 128 no. come please say me in detail
fast
by squarying number
8 √ 2 ²
= 8 √ 2 × 8 √2
= 64 × 2 = 128
thank you
your is right answer
Answered by
2
AB = BC....let AB = x= BC....(1)
by pythagoras theorem
AC ^2= AB^2. +BC^2
=>AC^2 = 2x^2 .....from (1)
=>(8root2)^2= 2x^2
=>64 * 2 = 2x^2
=>64 = x^2
=>8 = x....hence AB = 8unit.from (1)..
thank you
by pythagoras theorem
AC ^2= AB^2. +BC^2
=>AC^2 = 2x^2 .....from (1)
=>(8root2)^2= 2x^2
=>64 * 2 = 2x^2
=>64 = x^2
=>8 = x....hence AB = 8unit.from (1)..
thank you
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