Question

In ∆ABC ,∠B>90°,AD⊥BC,AB=9cm ,BC=8cm,BD=4cm then find AC? *​

Answer 1

It is given that ABC is a right angled triangle and BD is the altitude drawn from the right angle to the hypotenuse.

In ∆ DBA and ∆ DCB, we have :

∠BDA =∠CDB

∠DBA = ∠DCB = 90°

Therefore, by AA similarity theorem, we get : ∆DBA - ∆DCB

BD/CD =AD/BD

CD =BD²/ AD

CD =8×8/4 = 16 cm

Step-by-step explanation:

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