Question

In ▲ABC, ∠C = 90° , AC =5cm and BC = 12cm. The besector of ∠A meets BC at D. What is the length of AD?

Answer 1

Answer:

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ur answer....

In a triangle ABC , angle C=90° ,AC=5cm , BC=12cm. The bisector of angle a meets BC at D. The length of AD = 4.61cm^2.

Stepwise explanation is given below:

- It is given that the AC=5cm, BC=12cm.

area of triangle = (1/2) × base×height

- If we take AC as perpendicular then BC will be base.

- Then area of triangle = (1/2)× 5×12 = 30 cm²

also, by Pythagoras' theorem, 

BC² = AC² +BC²

       =(5)² + (12(² = 169

⇒BC = 13 cm

now, if AD is perpendicular then AB is the base

- Area of triangle = (1/2)× AB ×AD

⇒30 = (1/2)× 13×AD

⇒AD = 60/13 =4.61 cm

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