Question

In ∆ ABC, DE II BC, AD = x , BD = x + 1 , AE = x + 3 and CE = x + 5 , then find the value of x.​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

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Answer 2

Answer:

x = 3

Step-by-step explanation:

In Δ ABC, DE ∥ BC

∴ AD = AE

DB EC

(By basic proportionality theorem)

According to the Question

x = x + 3

x + 1 x + 5

Cross- multiplication

• x(x+5) = (x+1)(x+3)
• x² + 5x = x² + 4x + 3

using the identity,

(x+a)(x+b) = x² + (a+b)x + ab

• 5x - 4x = 3
• x = 3