The ratio of 'a' and 'b' 3:1, after 15 years their ratio would be 2:1,
then what are their present ages?
Answers
Answer:
Step-by-step explanation:
Given, ratio of age of A and B=3:1
Let the ages of A and B be 3x and x, respectively.
Now, 15 years hence,
age of A=3x+15 and age of B=x+15.
Then,
x+15
3x+15
=
1
2
⟹ 3x+15=2(x+15)
⟹ 3x+15=2x+30.
Transposing x terms to one side, we get,
⟹ 3x−2x=30−15
⟹x=15.
∴A's age =3×15=45 years
and B's age =x=15 years.
- The ratio of ages of 'a' and 'b' is 3:1
- After 15 years their ratio of ages would be 2:1
- Their present ages
Given that the ratio of ages of 'a' and 'b' is 3:1
So,
- Let the present age of a be '3z'
- Let the present age of b be '1z'
➠ 3z ⚊⚊⚊⚊ ⓵
➠ 1z ⚊⚊⚊⚊ ⓶
➠ 3z + 15
➠ 1z + 15
Also given that , after 15 years their ratio of ages would be 2:1
Thus ,
: ➜
⟮ Cross multiplying ⟯
: ➜ 1(3z + 15) = 2(z + 15)
: ➜ 3z + 15 = 2z + 30
: ➜ 3z - 2z = 30 - 15
: ➜ z = 15 ⚊⚊⚊⚊ ⓷
⟮ Putting z = 15 from ⓷ to ⓵ ⟯
: ➜ 3z
: ➜ 3(15)
: : ➨ 45
- Hence the present age of 'a' is 45 years
⟮ Putting z = 15 from ⓷ to ⓶ ⟯
: ➜ 1z
: ➜ 1(15)
: : ➨ 15
- Hence the present age of 'b' is 15 years
∴ The present ages of 'a' & 'b' are 45 years and 15 years respectively