In ΔABC, DE II BC intersecting AB at D and AC at E, AD = 1cm, DB = 3cm, AE = 1.5cm, AC =?
Answers
Answered by
3
In DABC
DE is parallel to BC
By Basic Proportionality Theorem
------------------- (1)
Given: AD = 1.5 cm, DB = 3 cm, AE = 1 cm
Let EC = ‘x’ cm
Applying in (1)
1.5x = 3
x =
x = 2 cm
EC = 2cm
DE is parallel to BC
By Basic Proportionality Theorem
------------------- (1)
Given: AD = 1.5 cm, DB = 3 cm, AE = 1 cm
Let EC = ‘x’ cm
Applying in (1)
1.5x = 3
x =
x = 2 cm
EC = 2cm
Similar questions