In ΔABC, express in terms of s.
Answers
Answered by
2
Solution :
**************************************
We know that ,
i ) r1 = s × tanA/2,
ii ) r2 = s × tanB/2
iii ) r3 = s× tanC/2
********************************
Given ,
r1 cotA/2 + r2 cotB/2 + r3 cotC/2
= s × tanA/2cotA/2
+ s × tanB/2cotB/2
+ s × tanC/2cotC/2
= s + s + s
= 3s
•••••
Given r1cotA/2+r2 cotB/2+r3 cotC/2
=
**************************************
We know that ,
i ) r1 = s × tanA/2,
ii ) r2 = s × tanB/2
iii ) r3 = s× tanC/2
********************************
Given ,
r1 cotA/2 + r2 cotB/2 + r3 cotC/2
= s × tanA/2cotA/2
+ s × tanB/2cotB/2
+ s × tanC/2cotC/2
= s + s + s
= 3s
•••••
Given r1cotA/2+r2 cotB/2+r3 cotC/2
=
Answered by
2
HELLO DEAR,
Answer:
Step-by-step explanation:
We know that ,
r1 = s × tanA/2,
r2 = s × tanB/2
r3 = s× tanC/2
Given ,
r1 cotA/2 + r2 cotB/2 + r3 cotC/2
= s × tanA/2cotA/2 + s × tanB/2cotB/2
+ s × tanC/2cotC/2
=> s + s + s
=> 3s
I HOPE IT'S HELP YOU DEAR,
THANKS
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