In ∆ABC, if ∠A= 48° , ∠B=56° then ∠C= ?
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We know that,
The sum of the three angles of any triangle is equal to 180°.
So, 58+48=106
180-106=74
58°+48°+74°=180°
So, ∠A= 48° ∠B= 48° ∠C=74°
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<A=48°
<B=56°
Then,<A+<B+<C =180° (Sum of all angles of a triangle)
=48°+56°+<C=180°
=104°+<C=180°
=<C=180°-104°
=<C=76°
Hence,<C=76°
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