Question

In ΔABC, if∠A-∠B=60 and ∠B-∠C=30 then find all the angles of ΔABC

Answer 1

Step-by-step explanation:

A-B=60

So, A=60+B ---1

B-C=30

So, C=B-30---2

Angle sum property of triangle : The sum of all angles of triangle is 180° .

So,∠A+∠B+C=180°

60+∠B+∠B+∠B-30=180

3∠B+30=180

3∠B = 150

∠B = 50

Substitute the value of B in 1 and 2

A=60+B=60+50 = 110

C=B-30= 50-30=20

So, ∠A= 110°,∠B = 50° , C=20°

Answer 2

Answer:

The angles are A=110°, B=50°, C=20°

Step-by-step explanation:

In a triangle, sum of all the angles is 180°

A+B+C=180°...............(1)

It is given that A-B=60°

A=60°+B

B-C=30

C=B-30°

Now Substituting the values of A and C in (1)

A+B+C=180°

60+B+B+B-30=180°

30 + 3B=180°

3B=150°

B=150/3

B=50°

A=60+B = 60+50 = 110°

C=B-30 = 50-30 = 20°

A=110°

B=50°

C=20°

PLS MARK BRAINLIEST