Question

In ΔABC, if ∠A + ∠B = 90°, cot B = 3/4 then the value of tan A is​

Answer 1

Answer:

∆ABC,

cot B=3/4

tan A= 4/3...

Answer 2

∠A+∠B=90°

∠B = 90° −∠A

cot B = 3/4

cot(90° −∠A)= 3/4

tan ∠A = 3/4 [cot (90°-∠A) = tan ∠A]

Hence tan ∠A = 3/4