In ∆ABC, if ,angle A= 60°, angleB=45°, then find angle C
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- angle A = 60 °
- angle B = 45 °
as known ,the sum of all the angles of a triangle is 180°
- so,angle A+angle B+angle C=180°
- therefore,60° +45°+angle C=180°
- 105°+angle C=180°
- angle C =180°-105°
- angle C =75°
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